list.pop segmentation fault

[davidbrochart]

The following code segfaults:

from lpython import i32

a: list[i32] = []
i: i32
for i in range(10):
    a.append(1)
    a.pop()

Commenting out a.pop() doesn't segfaults, or even replacing it with print(a.pop()).

[Thirumalai-Shaktivel]

Thanks @davidbrochart for trying out LPython!
The issue seemed to be fixed! Here is the current output:

from lpython import i32

a: list[i32] = []
i: i32
for i in range(10):
    a.append(1)
    if i > 5:
        a.pop()

print(a)

Output

$ lpython examples/expr2.py
[1, 1, 1, 1, 1, 1]

You can try out other programs. If you face any issues, please let us know!
Thank you!

[davidbrochart]

Awesome, keep up the great work! LPython rocks 🚀

[certik]

Thank you @davidbrochart for trying LPython and thank you for the excellent bug report. As you can see, it was fixed in 1h. Good bug reports we can fix quickly. :)