Problem
Currently, the code provided to the ?eval command is wrapped like this:
fn main() {
println!("{:?}", {
// CODE HERE
});
}
This has a small issue; when the code evaluates to a value with a lifetime, the code fails to compile, for example:
fn main() {
println!("{:?}", {
let a = 42;
&a
});
}
That's because &a exits the scope we explicitly declared with {}, but its lifetime is bound to something within that scope (a).
This is slightly confusing for bot users and also a bit annoying.
How to fix
You may be able to prevent this issue by wrapping the code differently. The following ?eval input...
/* line 1 */;
/* line 2 */;
/* line 3 */;
/* line 4 */
...would be translated to the following Rust code...
fn main() {
/* line 1 */;
/* line 2 */;
/* line 3 */;
println!("{:?}", /* line 4 */);
}
In other words: the code will be split up by semicolons and only the result of the last line is put into the println!(). The rest are top-level statements inside main.
I'm not sure if there are edge cases in which this approach would break
Problem
Currently, the code provided to the
?evalcommand is wrapped like this:This has a small issue; when the code evaluates to a value with a lifetime, the code fails to compile, for example:
That's because
&aexits the scope we explicitly declared with {}, but its lifetime is bound to something within that scope (a).This is slightly confusing for bot users and also a bit annoying.
How to fix
You may be able to prevent this issue by wrapping the code differently. The following ?eval input...
...would be translated to the following Rust code...
In other words: the code will be split up by semicolons and only the result of the last line is put into the
println!(). The rest are top-level statements inside main.I'm not sure if there are edge cases in which this approach would break