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ValidSudoku.java
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package explore.array;
import java.util.HashMap;
/**
* @author :DengSiYuan
* @date :2020/2/29 17:38
* @desc :36. 有效的数独
* 【题目】
* 判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。
* 数字 1-9 在每一行只能出现一次。
* 数字 1-9 在每一列只能出现一次。
* 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。
* 上图是一个部分填充的有效的数独。
* 数独部分空格内已填入了数字,空白格用 '.' 表示。
* 【示例】
* 输入:
* [
* ["5","3",".",".","7",".",".",".","."],
* ["6",".",".","1","9","5",".",".","."],
* [".","9","8",".",".",".",".","6","."],
* ["8",".",".",".","6",".",".",".","3"],
* ["4",".",".","8",".","3",".",".","1"],
* ["7",".",".",".","2",".",".",".","6"],
* [".","6",".",".",".",".","2","8","."],
* [".",".",".","4","1","9",".",".","5"],
* [".",".",".",".","8",".",".","7","9"]
* ]
* 输出: true
*
* 输入:
* [
* ["8","3",".",".","7",".",".",".","."],
* ["6",".",".","1","9","5",".",".","."],
* [".","9","8",".",".",".",".","6","."],
* ["8",".",".",".","6",".",".",".","3"],
* ["4",".",".","8",".","3",".",".","1"],
* ["7",".",".",".","2",".",".",".","6"],
* [".","6",".",".",".",".","2","8","."],
* [".",".",".","4","1","9",".",".","5"],
* [".",".",".",".","8",".",".","7","9"]
* ]
* 输出: false
* 解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
* 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
* 【说明】
* 一个有效的数独(部分已被填充)不一定是可解的。
* 只需要根据以上规则,验证已经填入的数字是否有效即可。
* 给定数独序列只包含数字 1-9 和字符 '.' 。
* 给定数独永远是 9x9 形式的。
*/
public class ValidSudoku {
public boolean isValidSudoku(char[][] board) {
// init data
HashMap<Integer, Integer>[] rows = new HashMap[9];
HashMap<Integer, Integer>[] columns = new HashMap[9];
HashMap<Integer, Integer>[] boxes = new HashMap[9];
for (int i = 0; i < 9; i++) {
rows[i] = new HashMap<>();
columns[i] = new HashMap<>();
boxes[i] = new HashMap<>();
}
// validate a board
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
char num = board[i][j];
if (num != '.') {
int n = (int)num;
int boxIndex = (i / 3 ) * 3 + j / 3;
// keep the current cell value
rows[i].put(n, rows[i].getOrDefault(n, 0) + 1);
columns[j].put(n, columns[j].getOrDefault(n, 0) + 1);
boxes[boxIndex].put(n, boxes[boxIndex].getOrDefault(n, 0) + 1);
// check if this value has been already seen before
if (rows[i].get(n) > 1 || columns[j].get(n) > 1 || boxes[boxIndex].get(n) > 1) {
return false;
}
}
}
}
return true;
}
}